具有多个条目的多个项目的组内最接近的日期时间匹配

import datetime

# 示例项目列表，每个项目包含日期和时间信息
projects = [
    {"name": "项目A", "datetime": datetime.datetime(2022, 1, 1, 10, 0, 0)},
    {"name": "项目B", "datetime": datetime.datetime(2022, 1, 1, 12, 0, 0)},
    {"name": "项目C", "datetime": datetime.datetime(2022, 1, 1, 14, 0, 0)},
    {"name": "项目D", "datetime": datetime.datetime(2022, 1, 1, 16, 0, 0)}
]

# 初始化最小差值和匹配项目对
min_difference = None
matching_projects = []

# 遍历每个项目，计算差值并更新最小差值和匹配项目对
for i in range(len(projects)):
    for j in range(i+1, len(projects)):
        difference = abs((projects[i]["datetime"] - projects[j]["datetime"]).total_seconds())
        if min_difference is None or difference < min_difference:
            min_difference = difference
            matching_projects = [(projects[i], projects[j])]
        elif difference == min_difference:
            matching_projects.append((projects[i], projects[j]))

# 输出最接近的日期和时间匹配项
for project_pair in matching_projects:
    print("最接近的日期和时间匹配项：")
    print("项目1：", project_pair[0]["name"], project_pair[0]["datetime"])
    print("项目2：", project_pair[1]["name"], project_pair[1]["datetime"])
    print("差值：", min_difference)