具有相同名称的多个文件-区分它们以进行检索的最佳方法是什么

import os
from datetime import datetime

# 假设有两个同名文件
file_path1 = '/path/to/file.txt'
file_path2 = '/path/to/another/file.txt'

# 获取文件的元数据
def get_file_metadata(file_path):
    stat = os.stat(file_path)
    return {
        'size': stat.st_size,
        'created': datetime.fromtimestamp(stat.st_ctime).strftime('%Y-%m-%d %H:%M:%S'),
        'modified': datetime.fromtimestamp(stat.st_mtime).strftime('%Y-%m-%d %H:%M:%S')
    }

# 获取文件的元数据
metadata1 = get_file_metadata(file_path1)
metadata2 = get_file_metadata(file_path2)

print(f"File 1 Metadata: {metadata1}")
print(f"File 2 Metadata: {metadata2}")

# 通过元数据检索文件
def find_file_by_metadata(metadata):
    for root, dirs, files in os.walk('/path/to'):
        for file in files:
            if file == 'file.txt':
                file_path = os.path.join(root, file)
                current_metadata = get_file_metadata(file_path)
                if current_metadata == metadata:
                    return file_path
    return None

# 检索特定文件
found_file_path = find_file_by_metadata(metadata1)
if found_file_path:
    print(f"Found file at: {found_file_path}")
else:
    print("File not found")