函数模板重载涉及指针的解析

#include<iostream>

template<typename T>
void print(T t) {
    std::cout << "Non-pointer type: " << t << std::endl;
}

template<typename T>
void print(T* t) {
    std::cout << "Pointer type: " << t << " points to " << *t << std::endl;
}

int main() {
    int a = 10;
    int* pa = &a;
    print(a);
    print(pa);
    return 0;
}

Non-pointer type: 10
Pointer type: 0x7ffd0c3c0d0c points to 10