#apply
#get answer grouped by col/row
d = matrix(1:30,5,6)
apply(d,1,mean) #row
apply(d,2,mean) #col...M <- array( seq(32), dim = c(4,4,2))
apply(M, 1, sum) #row
apply(M, c(1,2), sum) #row % col
colMeans...rapply(l,myFun)
#Result is a nested list like l, with values altered
rapply(l, myFun, how = "replace")
#tapply...x <- 1:20
y <- factor(rep(letters[1:5], each = 4))
tapply(x, y, sum)
参考资料
stackoverflow