删除嵌套循环

import numpy as np

# 假设我们有两个二维数组
array1 = np.array([[1, 2], [3, 4]])
array2 = np.array([[5, 6], [7, 8]])

# 使用向量化操作进行加法运算，而不是嵌套循环
result = array1 + array2
print(result)

def process_data(data, level=0):
    if level == len(data):
        return
    for item in data[level]:
        # 处理每个元素
        print(item)
        process_data(data, level + 1)

data = [[1, 2], [3, 4], [5, 6]]
process_data(data)

# 假设我们需要查找两个列表中的共同元素
list1 = [1, 2, 3, 4]
list2 = [3, 4, 5, 6]

# 使用集合（哈希表）进行快速查找
set1 = set(list1)
common_elements = set1.intersection(list2)
print(common_elements)

def merge_sorted_arrays(arrays):
    if len(arrays) == 1:
        return arrays[0]
    mid = len(arrays) // 2
    left = merge_sorted_arrays(arrays[:mid])
    right = merge_sorted_arrays(arrays[mid:])
    return merge(left, right)

def merge(left, right):
    result = []
    i = j = 0
    while i < len(left) and j < len(right):
        if left[i] < right[j]:
            result.append(left[i])
            i += 1
        else:
            result.append(right[j])
            j += 1
    result.extend(left[i:])
    result.extend(right[j:])
    return result

arrays = [[1, 3, 5], [2, 4, 6], [0, 7, 8]]
sorted_array = merge_sorted_arrays(arrays)
print(sorted_array)