我需要得到所有aid的值,这些值具有cid != 40和cid= 39 (多到多连接)SELECT DISTINCT aid FROM ac_branch WHERE aid IN (SELECTaid FROM ac_branch WHERE cid = 39);
SELECT DISTINCT aid FROM ac_branch WHERE aid IN (SELECT aid FROMac_branch WHERE cid !
company one ( cid = 1 ) type 'product' description 'hello ive updated my second product';如何从我的公司获得所有的feeds.description (这里的示例是cid =1) ?这里是我的简单pdo,以获得我的。如果推特获得了我所有的朋友地位(我跟踪的朋友)据说,irc mysql的一些好人会使用join