我尝试通过标准获取用户,但得到如下错误java.lang.IllegalArgumentException: org.hibernate.hql.internal.ast.QuerySyntaxException: unexpected token: '{test%,testuser6,%ana%}' near line 1, column 108 [
SELECT jpauser FROM com.abc.domain.jpa.JpaUser jpauser WHERE jpauser.username like ANY('{test%,testuse