请描述您的问题
标题:2017腾讯云11.11大促 给你实实在在的优惠
地址:https://cloud.tencent.com/act/double11?fromSource=gwzcw.592705.592705.592705
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def get_second_largest(nums):
largest = nums[0]
second_largest = nums[0]
for i in range(1, len(nums)):
if nums[i] > largest:
second_largest = largest
largest = nums[i]
elif nums[i] > second_largest:
second_largest = nums[i]
re
我需要保存4个最大数字的索引,例如,我需要获取第10,9,7,5行的索引 5.0259327
4.7127487
4.8435524
4.8538644
5.1048996
6.2441973
5.9413803
6.2912638
5.1117512
5.8309519
5.7419509
6.9663477
5.9958319
6.9519781
6.5802736
6.7327558
7.6765878 我用过 [mA,nA]=max(distA)
where mA is the row and nA is the column 在获得一个最大数时,我想不出如何选择另一个最大数而不重
在这里,我编写了从array.But打印最大和第二大数字的代码,当我的数组中有最大的数字两次时,它的打印是最大的和第二大的,就像same.Can告诉我在哪里做mistakes.This是我的代码一样。
int arr[] = {96, 1, 23, 47, 81, 92, 52, 48, 56, 66, 65, 96, 81, 6};
int largest = arr[0];
int secondLargest = arr[0];
// check the condition
for (int i = 0; i < arr.length; i++) {
public static void main(String[] args) {
int num;
int large;
int small;
int secondLarge;
Scanner scan = new Scanner(System.in);
System.out.print("Input a number: ");
num = scan.nextInt();
large = num;
small = num;
secondLarge = num;
for (int x =