另一个帮助，现在我想知道如何通过其他矩形删除碰撞矩形？

class Rectangle:
    def __init__(self, x, y, width, height):
        self.x = x
        self.y = y
        self.width = width
        self.height = height

def is_colliding(rect1, rect2):
    return (rect1.x < rect2.x + rect2.width and
            rect1.x + rect1.width > rect2.x and
            rect1.y < rect2.y + rect2.height and
            rect1.y + rect1.height > rect2.y)

def remove_colliding_rectangles(rectangles):
    non_colliding = []
    for i in range(len(rectangles)):
        collides = False
        for j in range(i + 1, len(rectangles)):
            if is_colliding(rectangles[i], rectangles[j]):
                collides = True
                break
        if not collides:
            non_colliding.append(rectangles[i])
    return non_colliding

# 示例使用
rectangles = [
    Rectangle(0, 0, 10, 10),
    Rectangle(5, 5, 10, 10),
    Rectangle(20, 20, 10, 10)
]

remaining_rectangles = remove_colliding_rectangles(rectangles)
for rect in remaining_rectangles:
    print(f"Rectangle at ({rect.x}, {rect.y}) with size {rect.width}x{rect.height}")