可以从python中的字节码生成gremlin查询吗？

import dis
from gremlin_python.process.traversal import T

def bytecode_to_gremlin(bytecode):
    gremlin_query = "g"
    for instruction in bytecode:
        if instruction.opname == "LOAD_GLOBAL":
            gremlin_query += f".{instruction.argval}"
        elif instruction.opname == "LOAD_ATTR":
            gremlin_query += f".{instruction.argval}"
        elif instruction.opname == "LOAD_CONST":
            if isinstance(instruction.argval, str):
                gremlin_query += f".{instruction.argval}"
            elif isinstance(instruction.argval, int):
                gremlin_query += f".{T.valueOf(instruction.argval)}"
        elif instruction.opname == "CALL_FUNCTION":
            gremlin_query += "()"
        elif instruction.opname == "POP_TOP":
            gremlin_query = gremlin_query[:-3]
    return gremlin_query

# 示例 Python 函数
def sample_function():
    return g.V().hasLabel('person').has('age', 18).values('name')

# 编译 Python 函数成字节码
bytecode = dis.Bytecode(sample_function)

# 从字节码生成 Gremlin 查询
gremlin_query = bytecode_to_gremlin(bytecode)
print(gremlin_query)