在使用typescript时，如何处理express控制器方法参数？

import { Request, Response } from 'express';

class UserController {
  getUser(req: Request, res: Response): void {
    const userId: string = req.params.id;
    // 处理逻辑
  }
}

import { Request, Response } from 'express';

interface CreateUserRequest {
  name: string;
  email: string;
  password: string;
}

class UserController {
  createUser(req: Request, res: Response): void {
    const userData: CreateUserRequest = req.body;
    // 处理逻辑
  }
}

import { Request, Response } from 'express';

class UserController {
  getUsers(req: Request, res: Response): void {
    const page: number = req.query.page;
    const limit: number = req.query.limit;
    // 处理逻辑
  }
}

import { Request, Response } from 'express';

class UserController {
  getUser(req: Request, res: Response): void {
    const userId: string = req.params.id;
    // 处理逻辑
  }
}

import { Request, Response } from 'express';

class UserController {
  createUser(req: Request, res: Response): void {
    const name: string = req.body.name;
    const email: string = req.body.email;
    const password: string = req.body.password;
    // 处理逻辑
  }
}