在基于条件的嵌套列表中查找连续的True和False

def find_continuous_true_false(nested_list):
    result = []
    current_list = []
    
    for sublist in nested_list:
        if isinstance(sublist, list):
            current_list.extend(find_continuous_true_false(sublist))
        else:
            current_list.append(sublist)
    
    if current_list:
        current_value = current_list[0]
        current_count = 1
        
        for i in range(1, len(current_list)):
            if current_list[i] == current_value:
                current_count += 1
            else:
                result.append((current_value, current_count))
                current_value = current_list[i]
                current_count = 1
        
        result.append((current_value, current_count))
    
    return result

nested_list = [[True, True, False], [True, False, False, True], True, [False, False]]
result = find_continuous_true_false(nested_list)
print(result)

[(True, 2), (False, 1), (True, 1), (False, 2)]