,可以通过以下步骤来实现:
def find_subsequence(sequence):
subsequence = []
max_subsequence = []
for num in sequence:
if not math.isnan(num): # 判断是否为NaN值
subsequence.append(num)
else:
if len(subsequence) > len(max_subsequence):
max_subsequence = subsequence
subsequence = []
if len(subsequence) > len(max_subsequence):
max_subsequence = subsequence
return max_subsequence
def find_longest_subsequence(sequence_set):
longest_subsequence = []
for sequence in sequence_set:
subsequence = find_subsequence(sequence)
if len(subsequence) > len(longest_subsequence):
longest_subsequence = subsequence
return longest_subsequence
find_longest_subsequence
函数并传入序列集合,即可得到在序列集合中没有NaN值的最长子序列。这个方法的优势是简单易懂,通过遍历序列集合并使用条件判断来找到没有NaN值的子序列。它适用于需要在序列集合中查找没有NaN值的最长子序列的场景,例如数据分析、时间序列处理等。
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