在我们不知道有多少嵌套对象具有相同键的情况下，我如何循环遍历json对象的特定键？

def traverse_json(obj, key):
    if isinstance(obj, dict):
        for k, v in obj.items():
            if k == key:
                # 处理找到的特定键
                print(v)
            if isinstance(v, (dict, list)):
                traverse_json(v, key)
    elif isinstance(obj, list):
        for item in obj:
            traverse_json(item, key)

# 示例 JSON 对象
json_obj = {
    "name": "John",
    "age": 30,
    "address": {
        "street": "123 Street",
        "city": "New York"
    },
    "pets": [
        {
            "name": "Fluffy",
            "type": "cat"
        },
        {
            "name": "Barky",
            "type": "dog"
        }
    ]
}

# 循环遍历 "name" 键
traverse_json(json_obj, "name")