在数字字符串中添加破折号的优雅方法是什么？

import re

def add_dash_to_number_string(number_string):
    # 使用正则表达式匹配数字部分
    pattern = r'\d+'
    numbers = re.findall(pattern, number_string)

    # 将匹配到的数字部分替换为带有破折号的格式
    for number in numbers:
        number_with_dash = re.sub(r'(\d)(?=(\d{3})+$)', r'\1-', number)
        number_string = number_string.replace(number, number_with_dash)

    return number_string

# 示例调用
number_string = '1234567890'
result = add_dash_to_number_string(number_string)
print(result)  # 输出：1-234-567-890