在没有.sorted()的情况下在Python中对列表进行排序

my_list = [3, 1, 4, 1, 5, 9]
my_list.sort()
print(my_list)  # 输出：[1, 1, 3, 4, 5, 9]

my_list = [3, 1, 4, 1, 5, 9]
my_list.sort()
my_list.reverse()
print(my_list)  # 输出：[9, 5, 4, 3, 1, 1]

my_list = [3, 1, 4, 1, 5, 9]
sorted_list = sorted(my_list, key=lambda x: x)
print(sorted_list)  # 输出：[1, 1, 3, 4, 5, 9]

import functools

def my_compare(x, y):
    if x < y:
        return -1
    elif x == y:
        return 0
    else:
        return 1

my_list = [3, 1, 4, 1, 5, 9]
sorted_list = sorted(my_list, key=functools.cmp_to_key(my_compare))
print(sorted_list)  # 输出：[1, 1, 3, 4, 5, 9]