在编译时获取std::bind的类型

void foo(int x, int y) {
    // do something
}

struct MyClass {
    void bar(int x, int y) {
        // do something
    }
};

int main() {
    auto func1 = std::bind(foo, 1, 2);
    auto func2 = std::bind(&MyClass::bar, MyClass(), 3, 4);

    // 使用func1和func2进行调用
    func1();
    func2();

    return 0;
}

#include <iostream>
#include <typeinfo>
#include <functional>

void foo(int x, int y) {
    // do something
}

struct MyClass {
    void bar(int x, int y) {
        // do something
    }
};

int main() {
    auto func1 = std::bind(foo, 1, 2);
    auto func2 = std::bind(&MyClass::bar, MyClass(), 3, 4);

    std::cout << "func1 type: " << typeid(func1).name() << std::endl;
    std::cout << "func2 type: " << typeid(func2).name() << std::endl;

    return 0;
}

func1 type: class std::_Bind<void (*(int, int))(int, int)>
func2 type: class std::_Bind<void (MyClass::*(int, int))(int, int)>