在C中将双精度转换为整数时处理溢出

#include<iostream>
#include<limits>

int main() {
    double d = 1.234e308;
    if (d > std::numeric_limits<int>::max() || d < std::numeric_limits<int>::min()) {
        std::cout << "Overflow detected"<< std::endl;
    } else {
        int i = static_cast<int>(d);
        std::cout << "Converted double to int: " << i << std::endl;
    }
    return 0;
}