在Golang中如何在并发代码中延迟工作

package main

import (
    "fmt"
    "time"
)

func worker(id int, jobs <-chan int, results chan<- int) {
    for j := range jobs {
        fmt.Println("Worker", id, "started job", j)
        time.Sleep(1 * time.Second) // 延迟1秒
        fmt.Println("Worker", id, "finished job", j)
        results <- j * 2
    }
}

func main() {
    jobs := make(chan int, 5)
    results := make(chan int, 5)

    // 启动3个并发的worker
    for w := 1; w <= 3; w++ {
        go worker(w, jobs, results)
    }

    // 发送5个任务到jobs通道
    for j := 1; j <= 5; j++ {
        jobs <- j
    }
    close(jobs)

    // 获取结果
    for a := 1; a <= 5; a++ {
        <-results
    }
}