在Groovy中解压缩文件时遇到问题

import java.util.zip.ZipInputStream

def unzipFile(String filePath, String destinationPath) {
    def zipFile = new File(filePath)
    def destDir = new File(destinationPath)

    destDir.mkdirs()

    def zipIn = new ZipInputStream(new FileInputStream(zipFile))
    def entry = zipIn.nextEntry

    while (entry != null) {
        def newFile = new File(destDir, entry.name)
        if (entry.isDirectory()) {
            newFile.mkdirs()
        } else {
            newFile.withOutputStream { out ->
                zipIn.eachByte(1024) { buffer, len ->
                    out.write(buffer, 0, len)
                }
            }
        }
        zipIn.closeEntry()
        entry = zipIn.nextEntry
    }
    zipIn.close()
}

// 使用示例
unzipFile("/path/to/archive.zip", "/path/to/destination")