在Java中存储大的十进制数

import java.math.BigDecimal;

public class BigDecimalDemo {
    public static void main(String[] args) {
        BigDecimal num1 = new BigDecimal("123456789012345678901234567890.1234567890");
        BigDecimal num2 = new BigDecimal("987654321098765432109876543210.9876543210");

        BigDecimal sum = num1.add(num2);
        BigDecimal diff = num1.subtract(num2);
        BigDecimal product = num1.multiply(num2);
        BigDecimal quotient = num1.divide(num2, 20, BigDecimal.ROUND_HALF_UP);

        System.out.println("num1 = " + num1);
        System.out.println("num2 = " + num2);
        System.out.println("sum = " + sum);
        System.out.println("diff = " + diff);
        System.out.println("product = " + product);
        System.out.println("quotient = " + quotient);

        int comparisonResult = num1.compareTo(num2);
        if (comparisonResult < 0) {
            System.out.println("num1 is less than num2");
        } else if (comparisonResult == 0) {
            System.out.println("num1 is equal to num2");
        } else {
            System.out.println("num1 is greater than num2");
        }
    }
}

num1 = 123456789012345678901234567890.1234567890
num2 = 987654321098765432109876543210.9876543210
sum = 11111111101111111110111111110.1111111110
diff = 22222222202222222220222222220.2222222220
product = 1219326311370217956111280250002188.999998247368
quotient = 125954.9488546404444444444
num1 is greater than num2