在Python中搜索特定超链接后返回超链接的URL值

import requests
from bs4 import BeautifulSoup
import re

def get_url_from_link(url, link_text):
    response = requests.get(url)
    soup = BeautifulSoup(response.text, 'html.parser')
    links = soup.find_all('a', text=re.compile(link_text))
    urls = [link['href'] for link in links]
    return urls

# 示例用法
search_url = 'https://example.com'
link_text = 'example link'
urls = get_url_from_link(search_url, link_text)
print(urls)