在Xamarin.Forms中以正确的文件类型打开字符串

public interface IOpenFileService
{
    void OpenFile(string filePath);
}

[assembly: Dependency(typeof(OpenFileService))]
namespace YourAppName.Droid
{
    public class OpenFileService : IOpenFileService
    {
        public void OpenFile(string filePath)
        {
            // 获取文件的MIME类型
            string mimeType = MimeTypeMap.GetMimeType(filePath);

            // 创建一个Intent来打开文件
            Intent intent = new Intent(Intent.ActionView);
            intent.SetDataAndType(Android.Net.Uri.Parse("file://" + filePath), mimeType);
            intent.SetFlags(ActivityFlags.ClearWhenTaskReset | ActivityFlags.NewTask);

            // 启动Intent
            Android.App.Application.Context.StartActivity(intent);
        }
    }
}

private void OpenFileButton_Clicked(object sender, EventArgs e)
{
    string filePath = "path/to/your/file";
    DependencyService.Get<IOpenFileService>().OpenFile(filePath);
}