在python中删除X个时间量后的行

import datetime
import csv

data = []
with open('data.csv', 'r') as file:
    reader = csv.reader(file)
    for row in reader:
        data.append(row)

current_time = datetime.datetime.now()
delta = datetime.timedelta(days=X)  # X为要删除的时间量，可以是天数、小时数等
target_time = current_time - delta

filtered_data = []
for row in data:
    row_time = datetime.datetime.strptime(row[0], '%Y-%m-%d %H:%M:%S')  # 假设时间数据在每行的第一列
    if row_time >= target_time:
        filtered_data.append(row)

with open('filtered_data.csv', 'w', newline='') as file:
    writer = csv.writer(file)
    writer.writerows(filtered_data)