在react-native中有没有一个函数可以调用和内联显示外部应用？

import { Linking } from 'react-native';

const openTwitter = () => {
  Linking.openURL('twitter://user?screen_name=username')
    .catch((err) => console.error('An error occurred', err));
};

import { Linking } from 'react-native';

const checkTwitter = async () => {
  const isSupported = await Linking.canOpenURL('twitter://user?screen_name=username');
  if (isSupported) {
    console.log('Twitter is supported');
  } else {
    console.log('Twitter is not supported');
  }
};