在swift中将JSON数据显示到outlet

import UIKit

class ViewController: UIViewController {
    @IBOutlet weak var nameLabel: UILabel!
    @IBOutlet weak var ageLabel: UILabel!
    
    override func viewDidLoad() {
        super.viewDidLoad()
        
        // 假设你已经获取到了包含JSON数据的对象或字典
        let json = """
        {
            "name": "John Doe",
            "age": 25
        }
        """
        
        // 将JSON数据转换为Swift对象或字典
        if let jsonData = json.data(using: .utf8),
           let jsonObject = try? JSONSerialization.jsonObject(with: jsonData, options: []) as? [String: Any] {
            
            // 从JSON对象中提取所需的数据
            if let name = jsonObject["name"] as? String,
               let age = jsonObject["age"] as? Int {
                
                // 将数据显示到UILabel上
                nameLabel.text = name
                ageLabel.text = String(age)
            }
        }
    }
}