在typescript中使用map时大对象的解构

const bigObject = {
  name: 'John',
  age: 30,
  address: {
    city: 'New York',
    country: 'USA'
  }
};

const { name, age, address } = bigObject;
console.log(name); // 输出：John
console.log(age); // 输出：30
console.log(address); // 输出：{ city: 'New York', country: 'USA' }

const { name, age, address } = bigObject;
name = 'Tom'; // 错误，解构后的变量是只读的，无法修改
address.city = 'Los Angeles'; // 正确，可以修改解构后的对象的属性值
console.log(address); // 输出：{ city: 'Los Angeles', country: 'USA' }

const bigObject = {
  name: 'John',
  age: 30,
  address: {
    city: 'New York',
    country: 'USA'
  }
};

const modifiedObject = Object.keys(bigObject).map(key => {
  const { name, age, address } = bigObject;
  // 对解构后的属性进行操作
  // ...
  return { name, age, address };
});

console.log(modifiedObject);