答案:
基于其值对元组列表中的重复元组进行平均,可以通过以下步骤实现:
下面是一个示例代码(使用Python语言):
def average_duplicates(tuple_list):
# Step 1: Group tuples by their values
tuple_dict = {}
for t in tuple_list:
value = t[1] # Assuming the value is at index 1
if value in tuple_dict:
tuple_dict[value].append(t)
else:
tuple_dict[value] = [t]
# Step 2: Calculate average for each group
average_list = []
for value, tuples in tuple_dict.items():
total = sum(t[0] for t in tuples) # Assuming the value to be averaged is at index 0
average = total / len(tuples)
average_list.append(average)
# Step 3: Return the final result
return average_list
# Example usage
tuple_list = [(1, 10), (2, 20), (3, 10), (4, 20), (5, 30)]
result = average_duplicates(tuple_list)
print(result)
这段代码将元组列表[(1, 10), (2, 20), (3, 10), (4, 20), (5, 30)]
中的重复元组按照值进行分组,并计算每个值对应的元组的平均值。最终输出结果为[2.0, 3.0, 5.0]
,表示值为10的元组的平均值为2.0,值为20的元组的平均值为3.0,值为30的元组的平均值为5.0。
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