如何从函数中查询并获取最大值

def find_max(numbers):
    return max(numbers)

# 示例使用
numbers = [3, 6, 2, 8, 4]
print(find_max(numbers))  # 输出: 8

function findMax(numbers) {
    return Math.max(...numbers);
}

// 示例使用
const numbers = [3, 6, 2, 8, 4];
console.log(findMax(numbers));  // 输出: 8

import java.util.Arrays;
import java.util.List;

public class MaxFinder {
    public static <T extends Comparable<T>> T findMax(List<T> list) {
        return Collections.max(list);
    }

    public static void main(String[] args) {
        List<Integer> numbers = Arrays.asList(3, 6, 2, 8, 4);
        System.out.println(findMax(numbers));  // 输出: 8
    }
}

#include <iostream>
#include <vector>
#include <algorithm>

int findMax(const std::vector<int>& numbers) {
    return *std::max_element(numbers.begin(), numbers.end());
}

int main() {
    std::vector<int> numbers = {3, 6, 2, 8, 4};
    std::cout << findMax(numbers) << std::endl;  // 输出: 8
    return 0;
}

def find_max(numbers):
    if not numbers:
        return None  # 或者抛出自定义异常
    return max(numbers)

def find_max_by_custom_rule(numbers, rule):
    return sorted(numbers, key=rule)[-1]