如何从子进程中捕获sys.exit()？

import subprocess

def run_child_process():
    try:
        # 执行子进程
        child_process = subprocess.Popen(['python', 'child_script.py'], stdout=subprocess.PIPE, stderr=subprocess.PIPE)
        # 等待子进程执行完毕，并获取输出和错误信息
        output, error = child_process.communicate()
        # 检查子进程的返回值
        if child_process.returncode == 0:
            print("子进程执行成功")
            print("输出信息:", output.decode())
        else:
            print("子进程执行失败")
            print("错误信息:", error.decode())
    except Exception as e:
        print("捕获到异常:", str(e))

if __name__ == '__main__':
    run_child_process()