如何从长生不老的列表中获得最接近的数字

def find_closest_number(target, immortal_list):
    closest_number = None
    min_difference = float('inf')  # 初始化差值为无穷大

    for number in immortal_list:
        difference = abs(target - number)  # 计算差值的绝对值

        if difference < min_difference:
            min_difference = difference
            closest_number = number

    return closest_number

# 示例用法
target_number = 42
immortal_list = [1, 10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
closest_number = find_closest_number(target_number, immortal_list)
print("最接近的数字是:", closest_number)