如何从Django查询集中获取前4个对象

# 假设我们有一个名为MyModel的模型
first_four_objects = MyModel.objects.all()[:4]

# 获取前4个对象
first_four_objects = []
for _ in range(4):
    obj = MyModel.objects.first()
    if obj is not None:
        first_four_objects.append(obj)
        MyModel.objects.filter(id=obj.id).delete()  # 删除已获取的对象以避免重复

# 假设我们想要根据创建时间排序获取前4个对象
first_four_objects = MyModel.objects.order_by('-created_at')[:4]

# 获取前4个对象的id和name字段
first_four_objects = MyModel.objects.only('id', 'name').order_by('-created_at')[:4]

from django.shortcuts import render
from .models import MyModel

def my_view(request):
    # 使用切片获取前4个对象
    first_four_objects = MyModel.objects.all().order_by('-created_at')[:4]
    
    context = {
        'first_four_objects': first_four_objects,
    }
    return render(request, 'my_template.html', context)

{% for obj in first_four_objects %}
    <div>{{ obj.name }}</div>
{% endfor %}