如何从HashMap中仅打印前10个单词及其出现频率？

import java.util.*;

public class WordFrequency {
    public static void main(String[] args) {
        // 假设这是从某处获取的单词频率HashMap
        Map<String, Integer> wordFrequencyMap = new HashMap<>();
        wordFrequencyMap.put("apple", 5);
        wordFrequencyMap.put("banana", 3);
        wordFrequencyMap.put("cherry", 7);
        wordFrequencyMap.put("date", 2);
        wordFrequencyMap.put("elderberry", 4);
        wordFrequencyMap.put("fig", 1);
        wordFrequencyMap.put("grape", 6);
        wordFrequencyMap.put("honeydew", 8);
        wordFrequencyMap.put("kiwi", 9);
        wordFrequencyMap.put("lemon", 10);
        wordFrequencyMap.put("mango", 11); // 超过10个单词的示例

        // 将HashMap转换为List以便排序
        List<Map.Entry<String, Integer>> list = new ArrayList<>(wordFrequencyMap.entrySet());

        // 按出现频率降序排序
        list.sort((entry1, entry2) -> entry2.getValue().compareTo(entry1.getValue()));

        // 打印前10个单词及其出现频率
        int count = 0;
        for (Map.Entry<String, Integer> entry : list) {
            if (count >= 10) break;
            System.out.println("Word: " + entry.getKey() + ", Frequency: " + entry.getValue());
            count++;
        }
    }
}