如何从Java过滤器获取请求URL？

import javax.servlet.*;
import javax.servlet.http.HttpServletRequest;
import java.io.IOException;

public class URLFilter implements Filter {
    @Override
    public void init(FilterConfig filterConfig) throws ServletException {
        // 初始化操作
    }

    @Override
    public void doFilter(ServletRequest servletRequest, ServletResponse servletResponse, FilterChain filterChain) throws IOException, ServletException {
        HttpServletRequest request = (HttpServletRequest) servletRequest;
        String url = request.getRequestURL().toString();
        // 进行进一步处理或记录
        System.out.println("请求URL：" + url);

        // 继续执行过滤器链
        filterChain.doFilter(servletRequest, servletResponse);
    }

    @Override
    public void destroy() {
        // 销毁操作
    }
}