如何从Scala访问Java静态方法,给出它所驻留的类的别名

import java.lang.reflect.{Method, Modifier}

def invokeJavaStaticMethod[T](className: String, methodName: String, parameterTypes: Class[_]*): T = {
  val clazz = Class.forName(className)
  val method = clazz.getDeclaredMethod(methodName, parameterTypes: _*)
  if (Modifier.isStatic(method.getModifiers)) {
    method.invoke(null, parameterTypes.map(_.newInstance()): _*).asInstanceOf[T]
  } else {
    throw new IllegalArgumentException(s"Method $methodName is not static")
  }
}

public class MyJavaClass {
  public static String myStaticMethod(int i) {
    return "Hello, world! " + i;
  }
}

val result = invokeJavaStaticMethod[String]("MyJavaClass", "myStaticMethod", classOf[Int])
println(result) // 输出 "Hello, world! 0"