如何从for语句中的异步回调中获取结果

const promises = [];
for (let i = 0; i < 10; i++) {
  const promise = new Promise((resolve, reject) => {
    // 异步操作
    setTimeout(() => {
      resolve(i);
    }, 1000);
  });
  promises.push(promise);
}

Promise.all(promises)
  .then(results => {
    console.log(results); // 获取所有异步操作的结果
  })
  .catch(error => {
    console.error(error);
  });

async function asyncOperation(i) {
  return new Promise((resolve, reject) => {
    // 异步操作
    setTimeout(() => {
      resolve(i);
    }, 1000);
  });
}

async function getResult() {
  const results = [];
  for (let i = 0; i < 10; i++) {
    const result = await asyncOperation(i);
    results.push(result);
  }
  console.log(results); // 获取所有异步操作的结果
}

getResult().catch(error => {
  console.error(error);
});