如何从typescript中的扩展类中排除接口属性

interface BaseInterface {
  propA: string;
  propB: number;
  propC: boolean;
}

class ExtendedClass implements BaseInterface {
  propA: string;
  propB: number;
  propC: boolean;

  constructor(propA: string, propB: number, propC: boolean) {
    this.propA = propA;
    this.propB = propB;
    this.propC = propC;
  }
}

// 使用 Omit 排除 propB
type ExtendedWithoutPropB = Omit<ExtendedClass, 'propB'>;

const instance: ExtendedWithoutPropB = {
  propA: 'test',
  propC: true,
};

interface BaseInterface {
  propA: string;
  propB: number;
  propC: boolean;
}

class ExtendedClass implements BaseInterface {
  propA: string;
  propB: number;
  propC: boolean;

  constructor(propA: string, propB: number, propC: boolean) {
    this.propA = propA;
    this.propB = propB;
    this.propC = propC;
  }
}

// 使用 Pick 和剩余参数排除 propB
type ExtendedWithoutPropB = Pick<ExtendedClass, Exclude<keyof ExtendedClass, 'propB'>>;

const instance: ExtendedWithoutPropB = {
  propA: 'test',
  propC: true,
};