如何使用循环编写此代码(这是Tic Tac Toe代码-通过返回角色来确定游戏的胜利者)

# 初始化棋盘
board = [[' ' for _ in range(3)] for _ in range(3)]

# 定义玩家角色和当前角色
players = ['X', 'O']
current_player = players[0]

# 游戏是否结束的标志
game_over = False

def print_board():
    for row in board:
        print('|'.join(row))
        print('-----')

def check_win(player):
    # 检查行
    for row in board:
        if all(cell == player for cell in row):
            return True
    # 检查列
    for col in range(3):
        if all(row[col] == player for row in board):
            return True
    # 检查对角线
    if board[0][0] == board[1][1] == board[2][2] == player:
        return True
    if board[0][2] == board[1][1] == board[2][0] == player:
        return True
    return False

def check_draw():
    return all(cell != ' ' for row in board for cell in row)

while not game_over:
    print_board()
    print(f"当前玩家: {current_player}")
    
    # 等待玩家输入位置
    valid_move = False
    while not valid_move:
        try:
            row = int(input("请输入行数 (0-2): "))
            col = int(input("请输入列数 (0-2): "))
            if board[row][col] == ' ':
                valid_move = True
            else:
                print("此位置已被占用，请重新输入！")
        except (ValueError, IndexError):
            print("请输入有效的行数和列数！")
    
    # 更新棋盘状态
    board[row][col] = current_player
    
    # 检查胜利条件
    if check_win(current_player):
        print_board()
        print(f"恭喜玩家 {current_player} 胜利！")
        game_over = True
    elif check_draw():
        print_board()
        print("游戏结束，平局！")
        game_over = True
    else:
        # 切换当前玩家
        current_player = players[1] if current_player == players[0] else players[0]