如何使用相同的onItemClick访问两个列表视图中的项？

ListView listView1 = findViewById(R.id.listView1);
ListView listView2 = findViewById(R.id.listView2);

List<String> dataSource1 = new ArrayList<>();
dataSource1.add("Item 1");
dataSource1.add("Item 2");
dataSource1.add("Item 3");

List<String> dataSource2 = new ArrayList<>();
dataSource2.add("Item A");
dataSource2.add("Item B");
dataSource2.add("Item C");

ArrayAdapter<String> adapter1 = new ArrayAdapter<>(this, android.R.layout.simple_list_item_1, dataSource1);
ArrayAdapter<String> adapter2 = new ArrayAdapter<>(this, android.R.layout.simple_list_item_1, dataSource2);

listView1.setAdapter(adapter1);
listView2.setAdapter(adapter2);

listView1.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        // 处理列表视图1的点击事件
        String item = (String) parent.getItemAtPosition(position);
        Toast.makeText(MainActivity.this, "点击了列表视图1的项：" + item, Toast.LENGTH_SHORT).show();
    }
});

listView2.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        // 处理列表视图2的点击事件
        String item = (String) parent.getItemAtPosition(position);
        Toast.makeText(MainActivity.this, "点击了列表视图2的项：" + item, Toast.LENGTH_SHORT).show();
    }
});