如何使用Jackson将嵌套值解析为JSON数组中的列表

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.12.5</version>
</dependency>

public class Person {
    private String name;
    private int age;
    private List<String> hobbies;

    // 省略构造函数、getter和setter方法
}

import com.fasterxml.jackson.databind.ObjectMapper;

public class JsonParser {
    public static Person parseJson(String jsonString) throws IOException {
        ObjectMapper objectMapper = new ObjectMapper();
        return objectMapper.readValue(jsonString, Person.class);
    }
}

public class Main {
    public static void main(String[] args) {
        String jsonString = "{\"name\":\"John\",\"age\":30,\"hobbies\":[\"reading\",\"traveling\"]}";

        try {
            Person person = JsonParser.parseJson(jsonString);
            System.out.println("Name: " + person.getName());
            System.out.println("Age: " + person.getAge());
            System.out.println("Hobbies: " + person.getHobbies());
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}