如何使用jackson获得json响应？

<dependency>
    <groupId>com.fasterxml.jackson.core</groupId>
    <artifactId>jackson-databind</artifactId>
    <version>2.12.5</version>
</dependency>

public class Person {
    private String name;
    private int age;

    // 构造函数、getter和setter方法省略
}

import com.fasterxml.jackson.databind.ObjectMapper;

public class Main {
    public static void main(String[] args) throws Exception {
        Person person = new Person("John", 25);

        // 创建ObjectMapper对象
        ObjectMapper objectMapper = new ObjectMapper();

        // 将Java对象转换为JSON字符串
        String json = objectMapper.writeValueAsString(person);

        System.out.println(json);
    }
}

{"name":"John","age":25}

import com.fasterxml.jackson.databind.ObjectMapper;
import org.springframework.http.MediaType;
import org.springframework.web.bind.annotation.GetMapping;
import org.springframework.web.bind.annotation.RestController;

@RestController
public class PersonController {
    @GetMapping(value = "/person", produces = MediaType.APPLICATION_JSON_VALUE)
    public String getPerson() throws Exception {
        Person person = new Person("John", 25);

        // 创建ObjectMapper对象
        ObjectMapper objectMapper = new ObjectMapper();

        // 将Java对象转换为JSON字符串
        String json = objectMapper.writeValueAsString(person);

        return json;
    }
}