如何使用php从数据库中获取的值来呈现表单的选项？

<?php
// 连接数据库
$servername = "数据库服务器地址";
$username = "数据库用户名";
$password = "数据库密码";
$dbname = "数据库名";
$conn = new mysqli($servername, $username, $password, $dbname);

// 检查连接是否成功
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 执行查询
$sql = "SELECT id, name FROM options_table";
$result = $conn->query($sql);

// 检查查询结果
if ($result->num_rows > 0) {
    // 输出表单
    echo "<form>";
    echo "<select name='option'>";
    while ($row = $result->fetch_assoc()) {
        $id = $row['id'];
        $name = $row['name'];
        echo "<option value='$id'>$name</option>";
    }
    echo "</select>";
    echo "<input type='submit' value='提交'>";
    echo "</form>";
} else {
    echo "没有可用选项";
}

// 关闭数据库连接
$conn->close();
?>