如何使用pygame制作圆形对象跳转？

import pygame
import sys

# 初始化pygame
pygame.init()

# 创建窗口
window_width = 800
window_height = 600
window = pygame.display.set_mode((window_width, window_height))
pygame.display.set_caption("Jumping Circle")

# 创建一个圆形对象
circle_radius = 50
circle_color = (255, 0, 0)  # 红色
circle_pos_x = window_width // 2
circle_pos_y = window_height // 2
circle_speed = 5

def main():
    clock = pygame.time.Clock()

    while True:
        # 处理游戏退出事件
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                pygame.quit()
                sys.exit()

        # 获取键盘按键状态
        keys = pygame.key.get_pressed()
        if keys[pygame.K_UP]:
            circle_pos_y -= circle_speed
        if keys[pygame.K_DOWN]:
            circle_pos_y += circle_speed
        if keys[pygame.K_LEFT]:
            circle_pos_x -= circle_speed
        if keys[pygame.K_RIGHT]:
            circle_pos_x += circle_speed

        # 填充窗口背景色
        window.fill((255, 255, 255))

        # 创建圆形对象
        pygame.draw.circle(window, circle_color, (circle_pos_x, circle_pos_y), circle_radius)

        # 更新窗口显示
        pygame.display.flip()

        # 控制游戏帧率
        clock.tick(60)

if __name__ == '__main__':
    main()