如何使用xslt从数组中获取所有XML值？

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output method="xml" indent="yes"/>

  <xsl:template match="/">
    <root>
      <xsl:apply-templates select="array/item"/>
    </root>
  </xsl:template>

  <xsl:template match="item">
    <xsl:copy-of select="."/>
  </xsl:template>
</xsl:stylesheet>

import javax.xml.transform.*;
import javax.xml.transform.stream.*;

public class XSLTExample {
  public static void main(String[] args) throws Exception {
    // 定义数组
    String[] xmlArray = {
      "<item>XML 1</item>",
      "<item>XML 2</item>",
      "<item>XML 3</item>"
    };

    // 加载XSLT样式表
    Source xsltSource = new StreamSource("path/to/your/stylesheet.xslt");
    TransformerFactory transformerFactory = TransformerFactory.newInstance();
    Transformer transformer = transformerFactory.newTransformer(xsltSource);

    // 遍历数组并转换每个元素
    for (String xml : xmlArray) {
      Source xmlSource = new StreamSource(new StringReader(xml));
      Result result = new StreamResult(System.out); // 输出到控制台，你可以根据需要修改输出目标
      transformer.transform(xmlSource, result);
    }
  }
}