如何修改此正则表达式以提取英国邮政编码的左手和右手部分？

^([A-Z]{1,2}\d{1,2}[A-Z]?)\s*(\d[A-Z]{2})$

import re

postcode = "SW1A 1AA"
pattern = r"^([A-Z]{1,2}\d{1,2}[A-Z]?)\s*(\d[A-Z]{2})$"
match = re.match(pattern, postcode)

if match:
    left_hand = match.group(1)
    right_hand = match.group(2)
    print(f"Left hand: {left_hand}, Right hand: {right_hand}")
else:
    print("Invalid postcode")

Left hand: SW1A, Right hand: 1AA