如何像long一样在hibernate中生成字符串id？

import java.io.Serializable;
import java.util.UUID;
import org.hibernate.engine.spi.SharedSessionContractImplementor;
import org.hibernate.id.IdentifierGenerator;

public class StringIdGenerator implements IdentifierGenerator {

    @Override
    public Serializable generate(SharedSessionContractImplementor session, Object object) {
        return UUID.randomUUID().toString();
    }
}

import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.Id;

@Entity
public class MyEntity {

    @Id
    @GeneratedValue(generator = "string-id")
    private String id;

    // 其他属性和方法
}

<hibernate-configuration>
    <session-factory>
        <!-- 其他配置 -->
        <mapping class="com.example.MyEntity"/>
        <identifier-generator strategy="com.example.StringIdGenerator" class="string-id"/>
    </session-factory>
</hibernate-configuration>