如何创建具有相同元素的长度为x的列表？

def create_list_with_same_elements(element, x):
    return [element] * x

# 示例
element = 5
x = 10
result = create_list_with_same_elements(element, x)
print(result)  # 输出: [5, 5, 5, 5, 5, 5, 5, 5, 5, 5]

function createListWithSameElements(element, x) {
    return Array(x).fill(element);
}

// 示例
const element = 5;
const x = 10;
const result = createListWithSameElements(element, x);
console.log(result);  // 输出: [5, 5, 5, 5, 5, 5, 5, 5, 5, 5]

import java.util.ArrayList;
import java.util.List;

public class Main {
    public static List<Integer> createListWithSameElements(int element, int x) {
        List<Integer> list = new ArrayList<>();
        for (int i = 0; i < x; i++) {
            list.add(element);
        }
        return list;
    }

    public static void main(String[] args) {
        int element = 5;
        int x = 10;
        List<Integer> result = createListWithSameElements(element, x);
        System.out.println(result);  // 输出: [5, 5, 5, 5, 5, 5, 5, 5, 5, 5]
    }
}

using System;
using System.Collections.Generic;

class Program {
    static List<int> CreateListWithSameElements(int element, int x) {
        List<int> list = new List<int>();
        for (int i = 0; i < x; i++) {
            list.Add(element);
        }
        return list;
    }

    static void Main() {
        int element = 5;
        int x = 10;
        List<int> result = CreateListWithSameElements(element, x);
        Console.WriteLine(string.Join(", ", result));  // 输出: 5, 5, 5, 5, 5, 5, 5, 5, 5, 5
    }
}