如何只获取没有文件路径的文件名？

import os

file_path = "path/to/your/file.txt"
file_name = os.path.basename(file_path)
print(file_name)

import re

file_path = "path/to/your/file.txt"
file_name = re.findall(r'[^/\\]+$', file_path)
print(file_name[0])

file_path = "path/to/your/file.txt"
file_name = file_path.split("/")[-1]
print(file_name)

import os

file_path = "path/to/your/file.txt"
file_name = os.path.split(file_path)[-1]
print(file_name)