如何在下拉列表中显示sql表(php，html)

<?php
// 数据库配置
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "database_name";

// 创建连接
$conn = new mysqli($servername, $username, $password, $dbname);

// 检查连接
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 查询语句
$sql = "SELECT id, name FROM your_table";
$result = $conn->query($sql);

echo "<select name='dropdown'>";
if ($result->num_rows > 0) {
    // 输出数据
    while($row = $result->fetch_assoc()) {
        echo "<option value='". $row["id"]. "'>". $row["name"]. "</option>";
    }
} else {
    echo "<option>没有结果</option>";
}
echo "</select>";

$conn->close();
?>

$stmt = $conn->prepare("SELECT id, name FROM your_table WHERE id = ?");
$stmt->bind_param("i", $id); // "i" 指定参数类型为整数
$stmt->execute();
$result = $stmt->get_result();