如何在不使用dom4j修剪的情况下获得元素的原始值？

import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.DocumentBuilder;
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;

public String getOriginalValue(String xml, String xpathExpression) {
    try {
        // 创建一个DocumentBuilderFactory对象
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        // 创建一个DocumentBuilder对象
        DocumentBuilder builder = factory.newDocumentBuilder();
        // 使用InputSource将XML字符串转换为输入流
        InputSource inputSource = new InputSource(new StringReader(xml));
        // 解析XML文档，获取Document对象
        Document document = builder.parse(inputSource);
        
        // 使用XPath表达式定位到目标元素
        XPath xpath = XPathFactory.newInstance().newXPath();
        NodeList nodeList = (NodeList) xpath.evaluate(xpathExpression, document, XPathConstants.NODESET);
        
        // 获取目标元素的原始值
        String originalValue = "";
        for (int i = 0; i < nodeList.getLength(); i++) {
            Element element = (Element) nodeList.item(i);
            originalValue += element.getTextContent();
        }
        
        return originalValue;
    } catch (Exception e) {
        e.printStackTrace();
        return "";
    }
}

String xml = "<root><element>   Hello World   </element></root>";
String xpathExpression = "//element";
String originalValue = getOriginalValue(xml, xpathExpression);
System.out.println("原始值：" + originalValue);